Asked by tom
The solubility of a certain compound in ice-cold water is 0.22g in 100mL. Its solubility in hot water is 4.35g in 100mL What is the best possible percent recovery we can expect for the re-crystallization of this compound in water?
Answers
Answered by
DrBob222
I worked this last night for another student and thought too little information was given. Here is another take on it.
If we take a 4.35 g sample, it will require 100 mL of hot water to dissolve it. When it crystallizes in ice cold water, we lose 0.22 g of it. Therefore, we can recover 4.35-0.22 = 4.13g.
%recovery = (4.13/4.35)*100 = x
If we take a 4.35 g sample, it will require 100 mL of hot water to dissolve it. When it crystallizes in ice cold water, we lose 0.22 g of it. Therefore, we can recover 4.35-0.22 = 4.13g.
%recovery = (4.13/4.35)*100 = x
Answered by
M
Thank you so much drbob! Your explanation make sense! :D
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