Asked by Allison

Let f(x)=21−x^2
The slope of the tangent line to the graph of f(x) at the point (−4,5) is ______ .
The equation of the tangent line to the graph of f(x) at (−4,5) is y=mx+b for
m=______
and
b=_______.

Answers

Answered by Steve
f(x) = 21-x²
f'(x) = -2x

f'(-4) = 8

The line through (-4,5) with slope 8 is

(y-5)/(x+4) = 8

y = 8x +37

I think that's enough of these.
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