Asked by STEPHANIE
Given the indicated parts of triangle ABC with γ = 90°, approximate the remaining parts. (Round your answers for a and c to one decimal place.)
β = 51°31', b = 250.0
α = ° '
a =
c =
Given the indicated parts of triangle ABC with γ = 90°, approximate the remaining parts. (Round your answers for b and c to one decimal place.)
α = 27°50', a = 530
β = ° '
b =
c =
Given the indicated parts of triangle ABC with γ = 90°, express the third part in terms of the first two.
β, c; b
b =
Given the indicated parts of triangle ABC with γ = 90°, express the third part in terms of the first two.
α, a; b
b =
β = 51°31', b = 250.0
α = ° '
a =
c =
Given the indicated parts of triangle ABC with γ = 90°, approximate the remaining parts. (Round your answers for b and c to one decimal place.)
α = 27°50', a = 530
β = ° '
b =
c =
Given the indicated parts of triangle ABC with γ = 90°, express the third part in terms of the first two.
β, c; b
b =
Given the indicated parts of triangle ABC with γ = 90°, express the third part in terms of the first two.
α, a; b
b =
Answers
Answered by
Henry
1. tanB = b/a = 250 / a,
a = 250 / tanB = 250 / tan51.52 = 198.7
A = 90 - 51.52 = 38.5 deg.
c = b / cosA = 250 / cos38.5 = 319.4.
2. B = 90 - A = 90 - 27.83 = 62.17 deg.
tanA = a / b = 530 / b,
b = 530 / tanA = 530 / tan27.83 = 1004.
c = a / sinA = 530 / sin27.83 = 1135.3.
3. sinB = b/c,
b = csinB.
4. tanA = a/b,
b = a/tanA.
a = 250 / tanB = 250 / tan51.52 = 198.7
A = 90 - 51.52 = 38.5 deg.
c = b / cosA = 250 / cos38.5 = 319.4.
2. B = 90 - A = 90 - 27.83 = 62.17 deg.
tanA = a / b = 530 / b,
b = 530 / tanA = 530 / tan27.83 = 1004.
c = a / sinA = 530 / sin27.83 = 1135.3.
3. sinB = b/c,
b = csinB.
4. tanA = a/b,
b = a/tanA.
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