2H2O(g)-->2H2O(l) -88.0KJ
2H2O(l)-->2H2O(g) 88.0 KJ
+2H2O(g)-->O2+2H2 483.6 KJ
2H2O(l)-->O2+2H2 571.6 KJ
571.6 KJ/mol
Given the following thermodynamic data,
2H2O(g) → O2(g) + 2H2(g)
∆Hrxn = 483.6kJ
H2O(g) → H2O(l) ∆Hrxn = −44.0kJ
What is the molar heat of formation for liquid
water, H2O (l)?
Answer in units of kJ/mole
1 answer