A 0.38-kg particle has a speed of 2.0 m/s at point A and kinetic energy of 7.5 J at point B.

(a) What is its kinetic energy at A?
J

(b) What is its speed at point B?
m/s

(c) What is the total work done on the particle as it moves from A to B?

1 answer

a,b) KE= 1/2 mass*v^2

c) the work done is the difference in energies at A,B