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in the xy coordinate plane point b (-3,2) and point d (3,-4)are opposite vertices of square abcd if point h is the midpoint of line segment bc what is the area of triangle ahd ?
14 years ago

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Steve
If you plot the points, you can see that a = (-3,-4) and h = (0,2).

So, the base of ahd is the line ad with length 6. The height of the triangle is also 6.

So, A(ahd) = 1/2 * 6 * 6 = 18
14 years ago

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