A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If the mass of the ball is 0.12 kg and the pitcher has it in his hand over a distance of 1.79 m, what is the average force exerted by the pitcher on the ball?

Answer 1

a = (Vf^2 - (Vo)^2) / 2d,
a = ((45)^2 - 0) / 3.58 = 565.6m/s^2.

F = ma = 0.12 * 565.6 = 67.9N.