Asked by me
A 320.0 m tall tower is built on the Equator. How much faster (in m/s) does a point at the top of the tower move than a point at the bottom. The radius of the Earth is 6400 km.
Answers
Answered by
drwls
(R2 -R1)*w, where
w is the angular velocity of the Earth in radians/s
R2 and R1 are the distances of the top and bottom of the building from the center of the Earth.
Note that R2 - R1 is the height of the building, so you do not need to use the Earth's radius in the calculation.
w is the angular velocity of the Earth in radians/s
R2 and R1 are the distances of the top and bottom of the building from the center of the Earth.
Note that R2 - R1 is the height of the building, so you do not need to use the Earth's radius in the calculation.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.