A 320.0 m tall tower is built on the Equator. How much faster (in m/s) does a point at the top of the tower move than a point at the bottom. The radius of the Earth is 6400 km.

Answer 1

(R2 -R1)*w, where

w is the angular velocity of the Earth in radians/s

R2 and R1 are the distances of the top and bottom of the building from the center of the Earth.

Note that R2 - R1 is the height of the building, so you do not need to use the Earth's radius in the calculation.