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How much heat would be required to heat 1 gram of pure liquid water from 10C to 20C?

How would i approach this problem?
14 years ago

Answers

D
figured it out.
14 years ago
joker
20-10=10*1*4.18=41.8 joul/1 gm
1 cal = 4.18 joul
s.h.w=1 cal/gm
13 years ago

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