How much heat would be required to heat 1 gram of pure liquid water from 10C to 20C?
How would i approach this problem?
2 answers
figured it out.
20-10=10*1*4.18=41.8 joul/1 gm
1 cal = 4.18 joul
s.h.w=1 cal/gm
1 cal = 4.18 joul
s.h.w=1 cal/gm
0 answers