ln (1) = 0
ln(1.1) = .09531
dy/dx = .09531/.1 = .9531
ln 2 = .69315
ln 2.1 = .74194
dy/dx = .04879/.1 = .4879
ln 5 = etc
ln 10 = 2.30258
ln 10.1 = 2.31253
dy/dx = 0.09950 which is about 1/10
looks like 1/x in the end
10. For f(x)=lnx, construct tables, rounded to four decimals, near x=1, x=2, x=5, and x=10. Use tables to estimate f'(1), f'(2), f'(5) and f'(10). Then guess a general formula for f'(x).
I don't understand how to do number 11
11. Estimate f'(2) using the values of f in the table.
1 answer
1 answer