a person is standing with there feet 0.1m apart and length from shoulders to feet(pivot point) is 1.5m what is the minimal coefficient of static friction required so that the frictional force is at least 1.5 x as large as the external force toppling the person?
according to my professor i have the following info
Fa= Wx 0.1m/1.5m
m=70kg
W=70x9.81m/s=687
687x(0.1m/1.5m)=48.5N
equation for static friction is
Force of Friction(Ffr)= mu x normal force (Fn)
but i simply do not know how approach the problem? please help