Two particles are at the same point at the same time, moving in the same direction. Par- ticle A has an initial velocity of 9 m/s and an acceleration of 2.7 m/s2. Particle B has an initial velocity of 2.9 m/s and an acceleration of 4.2 m/s2.

At what time will B pass A? Answer in units of s

1 answer

the distance traveled will be identical.

distanceA=9t+1/2 *2.7 t^2
distanceB=2.9t+ 1/2 * 4.2 t^2

set them equal and solve for time t.