Asked by Bob
length in cm of one side of perfect cube of gold with a density of 18g/cc and mass of 25g?
How would i set up this equation? I don't know what length formula I would use, because I know that i am not supposed to just divide the density by the mass, because that would be incorrect. Maybe the length would be 1/4x = Mass x Density??
How would i set up this equation? I don't know what length formula I would use, because I know that i am not supposed to just divide the density by the mass, because that would be incorrect. Maybe the length would be 1/4x = Mass x Density??
Answers
Answered by
DrBob222
mass = volume x density
25g = volume x 18 g/cc
Solve for volume in cc (cubic centimeters) = 1.389 cc.
Volume of a cube = length^3
1.389cc = length^3
So take the cube root of both sides to find
length = cube root(1.389) = 1.1157 cm which rounds to 1.1cm to two significant figures.
25g = volume x 18 g/cc
Solve for volume in cc (cubic centimeters) = 1.389 cc.
Volume of a cube = length^3
1.389cc = length^3
So take the cube root of both sides to find
length = cube root(1.389) = 1.1157 cm which rounds to 1.1cm to two significant figures.
Answered by
Bob
Thank You So Much
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