Asked by Amanda
find the intercepts and graph the equation by plotting points.
Y=2-2x^2
Y=2-2x^2
Answers
Answered by
Henry
Y = 2 - 2x^2.
Y = -2x^2 + 2,
Let Y = 0 and calculate X:
-2x^2 + 2 = 0,
-2x^2 = -2,
x^2 = 1,
X = +-1. = X-intercepts.
Let X = 0 and calculate Y:
Y = -2*0^2 + 2 = 2 = Y-intercept.
h = Xv = -b / 2a = 0 / -4 = 0.
k = Yv = -2*0^2 + 2 = 2.
V(h,k) = V(0,2).
Use the following points for graphing:
(X,Y).
(-2,-6)
(-1,0)
V(0,2)
(1,0)
(2,-6).
Y = -2x^2 + 2,
Let Y = 0 and calculate X:
-2x^2 + 2 = 0,
-2x^2 = -2,
x^2 = 1,
X = +-1. = X-intercepts.
Let X = 0 and calculate Y:
Y = -2*0^2 + 2 = 2 = Y-intercept.
h = Xv = -b / 2a = 0 / -4 = 0.
k = Yv = -2*0^2 + 2 = 2.
V(h,k) = V(0,2).
Use the following points for graphing:
(X,Y).
(-2,-6)
(-1,0)
V(0,2)
(1,0)
(2,-6).
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