A stone is dropped from a high altitude and 3 s later another stone is projected downward with a speed of 150 ft/s. When and where will the second stone overtake the first? Ans. (a) 5.70 s (b) 520 ft
2 answers
How did u get the 5.7
h(1st stone)= h(2nd stone)
1/2 (g)(t^2) = Vot - 1/2 (g)(t^2)
let x= time of 2nd stone to reach 1st stone
1/2 (32.22)(x + 3) = 150(x) + 1/2 (32.22)(x^2)
x=2.7
total time=3+2.7=5.7s
height =1/2 (32.22)(5.7)^2= 523.4ft
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1/2 (g)(t^2) = Vot - 1/2 (g)(t^2)
let x= time of 2nd stone to reach 1st stone
1/2 (32.22)(x + 3) = 150(x) + 1/2 (32.22)(x^2)
x=2.7
total time=3+2.7=5.7s
height =1/2 (32.22)(5.7)^2= 523.4ft
message me to my linkedin account to answer more questions
3 answers