Question
Smitty's Bar and Grill has brand name recognition of 61% around the world. Assuming we randomly select 2 people. The assumptions of a Bernoulli process are met. What is the probability
a)exacatly 5 of the 12 recognize the name of Smitty's Bar and Grill?
b)5 or fewer recognize Smitty's Bar and Grill
c)more than 5 recognize Smitty's Bar and Grill?
d) no one in the sample ever heard of Smitty's Bar and Grill
a)exacatly 5 of the 12 recognize the name of Smitty's Bar and Grill?
b)5 or fewer recognize Smitty's Bar and Grill
c)more than 5 recognize Smitty's Bar and Grill?
d) no one in the sample ever heard of Smitty's Bar and Grill
Answers
Anonymous
i think it is b) beacuase thet had only asked 2 people how can they get results by asking two people they have to ask more than 2 people to see.
Reiny
I have a strong feeling that you have a typo, and that you meant to say,
"Assuming we randomly select 12 people. "
Please confirm.
"Assuming we randomly select 12 people. "
Please confirm.
Anonymous
if it is 12 people she meant then the answer would be c)
Reiny
These are not multiple choice answers, they are individual questions
Reiny
a) prob that exactly 5 out of 12 will recognize
= C(12,5)(.61)^5(.39)^7
= appr 0.0918
b)
prob = C(12,0)(.61)^0 (.39)^12 + C(12,1)(.61)^1 (.39)^11 + ... + C(12,5)(.61)^5 (.39)^7
c) prob = 1 - (answer to b)
d) prob = C(12,0)(.61)^0 (.39)^12
= .00001238
= C(12,5)(.61)^5(.39)^7
= appr 0.0918
b)
prob = C(12,0)(.61)^0 (.39)^12 + C(12,1)(.61)^1 (.39)^11 + ... + C(12,5)(.61)^5 (.39)^7
c) prob = 1 - (answer to b)
d) prob = C(12,0)(.61)^0 (.39)^12
= .00001238