Question
Find the dy/dt for each pair of functions y=x^2-5x , x=t^2+3
Answers
Reiny
from y = x^2 - 5x
dy/dx = 2x - 5
from x = t^2+3
dx/dt = 2t
dy/dt = (dy/dx)(dx/dt)
= (2x-5)(2t)
dy/dx = 2x - 5
from x = t^2+3
dx/dt = 2t
dy/dt = (dy/dx)(dx/dt)
= (2x-5)(2t)