Asked by Nikkie
What is the approximate volume of 0.095 M HCl needed to neutralize 0.25g of sodium carbonate. Hint: Write a balanced equation first.
Answers
Answered by
DrBob222
Na2CO3 + 2HCl ==> CO2 + H2O + 2NaCl
Here is a worked example of a stoichiometry problem. Remember moles = M x L.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Here is a worked example of a stoichiometry problem. Remember moles = M x L.
http://www.jiskha.com/science/chemistry/stoichiometry.html
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