Asked by ryan
If a man is fencing in a rectangular lot of grass next to the road and doesnt want to fence the side touching the road and has 248 feet of fence, whats the maximum area he can fence?
Answers
Answered by
Steve
If we use h and w for length and width, with length parallel to the road,
perimeter p = 2w+h = 248
Area = w*h = w(248-2w) = 248w - 2w^2
We want to maximize the area, so we take the derivative and set it to zero.
248-4w = 0
w = 62
So, h = 124
Maximum area = 62*124 = 7688 sq ft
For a given perimeter, a square has maximum area. Here, we use the road as one side, so we get to enclose two squares instead of one.
perimeter p = 2w+h = 248
Area = w*h = w(248-2w) = 248w - 2w^2
We want to maximize the area, so we take the derivative and set it to zero.
248-4w = 0
w = 62
So, h = 124
Maximum area = 62*124 = 7688 sq ft
For a given perimeter, a square has maximum area. Here, we use the road as one side, so we get to enclose two squares instead of one.
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