Asked by Anonymous
Indicate the concentration of each ion present in the solution formed by mixing the following. (Assume that the volumes are additive.)
(a) 50 mL of 0.100 M HCl and 10.0 mL of 0.510 M HCl
(b) 15.0 mL of 0.309 M Na2SO4 and 38.6 mL of 0.200 M KCl
(c) 3.50 g of NaCl in 40.2 mL of 0.372 M CaCl2 solution
(a) 50 mL of 0.100 M HCl and 10.0 mL of 0.510 M HCl
(b) 15.0 mL of 0.309 M Na2SO4 and 38.6 mL of 0.200 M KCl
(c) 3.50 g of NaCl in 40.2 mL of 0.372 M CaCl2 solution
Answers
Answered by
DrBob222
(A) moles HCl1 = M x L
moles HCl2 = M x L
moles mixture = total moles/total L.
B and C are about the same but the salts are not 1:1 therefore, you determine moles Na2SO4, for example, and multiply by 1 for moles Na^+ and multiply by 1 for sulfate ion.
moles HCl2 = M x L
moles mixture = total moles/total L.
B and C are about the same but the salts are not 1:1 therefore, you determine moles Na2SO4, for example, and multiply by 1 for moles Na^+ and multiply by 1 for sulfate ion.
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