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0.250g of phthalic acid is dissolved in 40.00cm^3 of 0.100 mol dm^-3 NaOH. It requires 11.80 cubic centimeters of 0.100 mol\dm^...Asked by Petty
0.250g of phthalic acid is dissolved in 40.00cm^3 of 0.100 mol dm^-3 NaOH. It requires 11.80 cubic centimeters of 0.100 mol\dm^-3 HCL fo neutralisation( to phenolphthalein) The mole ratio in which phthalic acid reacts with sodium hydroxide ihn 1:2
(a) Calculate the moles of excess NaOH reacted with HCL
(b)Calculate the moles of phthalic acid used
(c) Calculate the molecular mass of phthalic acid
(a) Calculate the moles of excess NaOH reacted with HCL
(b)Calculate the moles of phthalic acid used
(c) Calculate the molecular mass of phthalic acid
Answers
Answered by
luke
0.250 g of phthalic acid is dissolved in 40.00 cm3 of 0.100 mol dm-3 NaOH. It
requires 11.80 cm3 of 0.100 mol dm-3 HCl for neutralisation (to
phenolphthalein). The mole ratio in which phthalic acid reacts with sodium
hydroxide is 1:2.
requires 11.80 cm3 of 0.100 mol dm-3 HCl for neutralisation (to
phenolphthalein). The mole ratio in which phthalic acid reacts with sodium
hydroxide is 1:2.
Answered by
Seiniana
What's the answers for the question?
Answered by
Caleb talu
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