Asked by Anonymous

AD is an altitude of an isosceles triangle ABC in which AB=AC. Show that AD bisects BC.
Answered by drwls
The two halves of the triangle are congruent. (Proof: SAS. Side, bisected half angle A/2 and common side are equal)

Therefore the two lengths BD and DB are equal and BC is bisected.
Answered by Aarti
Aansweer
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