Asked by Chin Po
                The width of a basketball court is 1 m more than half the length. If The area of the court is 364m^2, find the length and width.
how would you solve this problem?
please help me.. =)
            
        how would you solve this problem?
please help me.. =)
Answers
                    Answered by
            Chin Po
            
    May someone help me?
    
                    Answered by
            Damon
            
    (.5L+1)(L) = 364
.5 L^2 + L - 364 = 0
L^2 + 2 L - 728 = 0
(L-26)(L+28) = 0
L = 26
w = 13+1 = 14
    
.5 L^2 + L - 364 = 0
L^2 + 2 L - 728 = 0
(L-26)(L+28) = 0
L = 26
w = 13+1 = 14
                    Answered by
            Chin Po
            
    thank you!!
    
                    Answered by
            Damon
            
    To figure out the 26 and 28, I knew the factors must differ by 2 and multiply to 728 so I took the sqrt of 728 which is 26.98 or about 27. then one above is 28 and one below is 26
    
                    Answered by
            Chin Po
            
    how would you solve this one? 
the sum of the squares of two consecutive even integers is 452. Find the integers.
i think i know that..
x=1st # and
x+2= 2nd #?
    
the sum of the squares of two consecutive even integers is 452. Find the integers.
i think i know that..
x=1st # and
x+2= 2nd #?
                    Answered by
            Damon
            
    n and n+2
n^2 + (n+2)^2 = 452
yes
    
n^2 + (n+2)^2 = 452
yes
                    Answered by
            Chin Po
            
    thnx
and if it says the sum of the squares of three consecutive positive integers is 194. Find the integers.
is it x=1st
x+3= 2nd
x+5= 3rd?
and would adding all these give me a result of 194?
    
and if it says the sum of the squares of three consecutive positive integers is 194. Find the integers.
is it x=1st
x+3= 2nd
x+5= 3rd?
and would adding all these give me a result of 194?
                    Answered by
            Damon
            
    n^2 + n^2 + 4 n + 4 = 452
2n^2 + 4 n - 448 = 0
(2n-28)(n+16) = 0
n = 14
n+2 = 16
    
2n^2 + 4 n - 448 = 0
(2n-28)(n+16) = 0
n = 14
n+2 = 16
                    Answered by
            Damon
            
    no, it said consecutive positive integers, difference is one
    
                    Answered by
            Damon
            
    I would use
n-1
n
n+1
    
n-1
n
n+1
                    Answered by
            Damon
            
    (n-1)^2 + n^2 + (n+1)^2 = 194
n^2 -2 n + 4 + n^2 + n^2 + 2 n + 4 = 194
    
n^2 -2 n + 4 + n^2 + n^2 + 2 n + 4 = 194
                    Answered by
            Damon
            
    whoops
n^2 - 2n + 1 + n^2 +n^2 + 2 n + 1 = 194
3n^2 = 192
n^2 = 64
n = 8
so
7 , 8, 9
    
n^2 - 2n + 1 + n^2 +n^2 + 2 n + 1 = 194
3n^2 = 192
n^2 = 64
n = 8
so
7 , 8, 9
                    Answered by
            Damon
            
    that means that
7, 8, 9 is a right triangle by the way
    
7, 8, 9 is a right triangle by the way
                    Answered by
            Damon
            
    Oh no it does not! the sum of the squares of two of them must equal squre of third to be a right triangle.
    
                    Answered by
            Chin Po
            
    thank you so much! i appreciate the help
    
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