Asked by Corinthia
A sample of aluminum sulfate 18-hydrate, Al2(SO4)3 · 18 H2O, containing 157.0 mg is dissolved in 1.000 L of solution. Calculate
(a) molarity of Al2(SO4)3
(b) molarity of SO42-
(c) molality of Al2(SO4)3, assuming that the density of the solution is 1.00 g/mL
(a) molarity of Al2(SO4)3
(b) molarity of SO42-
(c) molality of Al2(SO4)3, assuming that the density of the solution is 1.00 g/mL
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