Asked by Roger

Suppose the function G(t) represents a test grade (out of 100 points) as a function of hours studied. If
G(t)=-0.046t^3+0.915t^2+38.005 points, what is (dG/dt)when t=4? Round your answer to the nearest point per hour.


a. 50 points per hour

b. 3 points per hour

c. 5 points per hour

d. 7 points per hour

e. 20 points per hour
Answered by Writeacher
Your umpteen posts have been removed.

Once you write up <b>WHAT YOU THINK</b>, please re-post, and someone here will be happy to comment.
Answered by Roger
WHY ARE YOU DELETING MY POSTS?
Answered by Writeacher
To quote one of our very good math and science tutors: <b>"You will find here at Jiskha that long series of questions, posted with no evidence of effort or thought by the person posting, will not be answered. We will gladly respond to your future questions in which <u>your thoughts</u> are included."</b>
Answered by Anonymous
Derivative of t ^ 3 = 3 * t ^ 2

Derivative of t ^ 2 = 2 * t

Derivative of 38.005 = 0

dG / dt = - 0.046 * 3 * t ^ 2 + 0.915 * 2 t + 0 = - 0.138 * t ^ 2 + 1.83 * t

When t = 4

then :

dG / dt = - 0.138 * 4 ^ 2 + 1.83 * 4

dG / dt = - 0.138 * 16 + 7 . 32

dG / dt = - 2.208 + 7.32

dG / dt = 5.112


Rounded to the nearest point per hour :

dG / dt = 5 points per hour

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