Asked by Jimmy
Consider the air over a city to be a box 100km on a side that reaches up to an altitude of 1.0 km. THe air is blowing into the box along one of its sides with a speed of 4 m/s. Suppose an air pollutant with a reaction rate of K = 0.20/hr is emitted into the box at a total mass loading rate of 10 kg/s. Find the steady state concentration if the air in the box is assumed to be perfectly mixed.
Answers
Answered by
aurelio
what would be the CO consentration in the box?
Answered by
Harley Lara
V= 100*100*1 = 10000 km^3
Q = 4/1000*1*100 = 0.4 km^3/s
m (loading) = 10kg/s, k = 0.20/hr
1 km^3 = 10^12 L (if u want kg/L as concentration)
Cin = 10kg/s / 0.4 km^3/s = 25 kg/km^3
for CSTR: Cout = Cin/(1+k*t), t = V/Q = 25000 s or 6.94 hr
Cout = 25/(1+0.20*6.94) = 10.47 kg/km^3
Q = 4/1000*1*100 = 0.4 km^3/s
m (loading) = 10kg/s, k = 0.20/hr
1 km^3 = 10^12 L (if u want kg/L as concentration)
Cin = 10kg/s / 0.4 km^3/s = 25 kg/km^3
for CSTR: Cout = Cin/(1+k*t), t = V/Q = 25000 s or 6.94 hr
Cout = 25/(1+0.20*6.94) = 10.47 kg/km^3
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