identify the type of curve and sketch the graph of y2-2x+6y+5=0

Answer 1

Assuming y2 means y^2, then we have a parabola, opening to the right:

2x = y^2 + 6y + 5
= (y+1)(y+5)

So it has zeroes at y=-1, y=-5, axis of symmetry at y = -3, vertex at (-2,-3).