Asked by Roger

For the given equation, find the slope of the tangent to the curve at the point (-4,2).
y^2+8y+x^2+8x-4=0

A. -1.50
B. -0.50
C. -2.00
D. 0.00
E. UNDEFINED
Answered by bobpursley
2yy'+8y'+2x+8=0

y'= (-2x-8)/(2y+8) check that.

y'=0
Answered by Roger
Is it undefined or just 0.00?
Answered by bobpursley
Is it 0/0? that is undefined. If it is 0/realnumber, it is zero.
Answered by Roger
ok, thanks.
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