Asked by Thi
A small mailbag is released from a helicopter that is descending steadily at 2.87 m/s.
a)After 5.00 s, what is the speed of the mailbag?
b)How far is it below the helicopter?
a)After 5.00 s, what is the speed of the mailbag?
b)How far is it below the helicopter?
Answers
Answered by
bobpursley
a. vf=vi+gt
g is downward, as is vi
b. distance= vi*t+1/2 g t^2 again, vi, g are negative.
g is downward, as is vi
b. distance= vi*t+1/2 g t^2 again, vi, g are negative.
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