Asked by calculus

cos^-1(cos15pi/6)
Answered by Steve
Not much calculus here, but here goes:

by definition
cos(cos^-1(x)) = x
cos^-1(cos(x)) = x

for x in suitable ranges. Now, for cos^-1(x) the function takes on principal values between 0 and π.

So, cos^-1(cos(15π/6)) = cos^-1(cos 5π/2) = cos^-1(0) = π/2.
There are no AI answers yet. The ability to request AI answers is coming soon!