John kicks a soccer ball 12 m/s at an angle of 40.0 degrees above the horizontal. What is the ball's maximum height? Where does the ball land?

Answer 1

vertical velocity=12*sin40

consider the vertical: at the top, vertical velocity is zero

Vtop=Vinitial-gt
0=12sin40-9.8 t solve for t, then solve for height
hf=12sin40*t -1/2 g t^2

Horizontal : total time in air is 2t.

distance=horizontal velocity*2t
= 12 cos40 * 2t