A ball swings in a vertical circle at the end of a rope 1.50 m long. When the ball is 35.9° past the lowest point on its way up, its total acceleration is (-22.5 i + 20.2 j)m/s^2. Find radial acceleration?
3 answers
29.53 m/s^2
30.24m/s
a = sqrt (vx^2+vy^2)
a=sqrt (-22.5)^2+(20.2)^2
a=30.24m/s^2
a=sqrt (-22.5)^2+(20.2)^2
a=30.24m/s^2
1 answer