Asked by hannah
Amy threw a ball of mass m=0.79 kg horizontally with an initial velocity v=33.4 m/s from a height h=1.9 m. What is the kinetic energy of the ball just before it touches the ground? Express your answer in Joules and use 10 m/s2 for g.
Answers
Answered by
Damon
the initial ke of (1/2) m v^2 + the loss in potential energy due to falling of m g h
(1/2) .79 (33.4)^2 + .79 * 10 * 1.9
(1/2) .79 (33.4)^2 + .79 * 10 * 1.9
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