Asked by Aha
A method for recycling scrap aluminum converts it to alum [potassium aluminum sulfate dodecahydrate, KAl(SO4)2·12H2O].
What is the maximum amount of alum (in metric tons) that can be prepared from 3.12 metric tons of scrap aluminum (1 metric ton = 1000 kg)?
What is the maximum amount of alum (in metric tons) that can be prepared from 3.12 metric tons of scrap aluminum (1 metric ton = 1000 kg)?
Answers
Answered by
DrBob222
This is a simple stoichiometry problem. Here is a worked example of one. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
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