Asked by ANNA

WHAT IS THE PERIMETER OF A SQUARE WHOSE VERTICLES ARE A(-4,-3), B(-5,1), C(-1,2), AND D(0,-2)?

Answers

Answered by Mgraph
AB=sqrt(((-5)-(-4))^2+(1-(-3))^2)=
sqrt((-1)^2+4^2)=sqrt(17)

The perimeter=4*AB
Answered by ANNA
THANK YOU
Answered by Mgraph
You're welcome.
Answered by Charles
P=4.(17)^1/2
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