Asked by ANNA

WHAT IS THE PERIMETER OF A SQUARE WHOSE VERTICLES ARE A(-4,-3), B(-5,1), C(-1,2), AND D(0,-2)?

14 years ago

Answered by Mgraph

AB=sqrt(((-5)-(-4))^2+(1-(-3))^2)=
sqrt((-1)^2+4^2)=sqrt(17)

The perimeter=4*AB

14 years ago

Answered by ANNA

THANK YOU

14 years ago

Answered by Mgraph

You're welcome.

14 years ago

Answered by Charles

P=4.(17)^1/2

14 years ago

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