Asked by andrea
If 0.694 grams of pure KHP are needed to exactly neutralize 30.5 mL of a calcium hydroxide solution, what is the concentration (in molarity) of the base solution?
Answers
Answered by
DrBob222
2KHP + Ca(OH)2 ==> 2H2O + Ca(PK)2
moles KHP = grams/molar mass
Convert moles KHP to moles Ca(OH)2 (multiply by 2).
M Ca(OH)2 = moles Ca(OH)2/L Ca(OH)2.
moles KHP = grams/molar mass
Convert moles KHP to moles Ca(OH)2 (multiply by 2).
M Ca(OH)2 = moles Ca(OH)2/L Ca(OH)2.
There are no AI answers yet. The ability to request AI answers is coming soon!