Question

Two children are playing on two trampolines. The first child can bounce 1.6 times higher than the second child. The initial speed up of the second child is 5.2 m/s.
(a) Find the maximum height the second child reaches.
(b) What is the initial speed of the first child?
(c) How long was the first child in the air?

Answer 1

Yo= 0m
h=?
A=g=9.8m/s^2
Child A:
Voa= ?
Ya= 1.6h
Ta= ?
Child B:
Vob= 5.2 m/s
Yb= h
a) Vob^2 = 2AYb
Yb= Vob/2A
h= (5.2 m/s)^2/(2(9.8m/s^2))
h= 1.37m

b) Voa=?
Voa^2=2AYa
Voa= sqrt(2AYa)
Voa= sqrt(2(9.8m/s^2)(1.6(1.37)))
Voa= 6.55m/s

c) sorry but i can't figure out how to do c