Asked by Anonymous

If you used the 8900 kilojoules you expend in energy in one day to heat 46000 {\rm g} of water at 25^\circ {\rm C}, what would be the rise in temperature?
Answered by DrBob222
q = mass water x specific heat water x delta T. Solve for delta T. Add 25 if you want to know the final T.
Answered by bob
0.015
There are no AI answers yet. The ability to request AI answers is coming soon!