INSERT THE SEVEN ARITHMETIC MEANS BETWEEN 3 AND 9
6 answers
Which arithmetic means?
THE QUESTION JUST SAYS INSERT SEVEN ARITHMETIC MEANS BETWEEN 3 AND 9
You need a set of data to have an arithmetic mean.
http://www.mathgoodies.com/lessons/vol8/mean.html
http://www.mathgoodies.com/lessons/vol8/mean.html
THIS IS FOR ALGEBRA/PRE-CALCULUS MATH. I POSTED IT JUST AS THE TEACHER WROTE IT.
terms:
3, 3+d, 3+2d, 3+3d, 3+ 4d, 3+5d, 3+6d, 3+7d , 9
so we now have 9 terms
a = 3,
term(9) = a+8d = 9
3 + 8d = 9
d = 6/8 = 3/4 or .75
the 7 terms are:
3.75, 4.5, 5.25, 6, 6.75, 7.5, 8.25
3, 3+d, 3+2d, 3+3d, 3+ 4d, 3+5d, 3+6d, 3+7d , 9
so we now have 9 terms
a = 3,
term(9) = a+8d = 9
3 + 8d = 9
d = 6/8 = 3/4 or .75
the 7 terms are:
3.75, 4.5, 5.25, 6, 6.75, 7.5, 8.25
Or you could go on the long way method
Supposedly the question doesn't only have numbers e.g (3p-q) and (-13p+7q)
Where (3p-q) is the first term and (-13p+7q) is the ninth term.
You take the 1st term add it with the last and divide the sum by 2
But remember that it will give you the 5th term
Then take the sum of the 5th and the 1st to get the 3rd term.
You do that until you get the rest.
Now let's look at your question [(3+9)/2]= 6 right? That's the 5th term
[(3+6)/2]=4.5 which is the 3rd term
So you go on to find the rest.
Good luck :-)
Supposedly the question doesn't only have numbers e.g (3p-q) and (-13p+7q)
Where (3p-q) is the first term and (-13p+7q) is the ninth term.
You take the 1st term add it with the last and divide the sum by 2
But remember that it will give you the 5th term
Then take the sum of the 5th and the 1st to get the 3rd term.
You do that until you get the rest.
Now let's look at your question [(3+9)/2]= 6 right? That's the 5th term
[(3+6)/2]=4.5 which is the 3rd term
So you go on to find the rest.
Good luck :-)