Asked by Anthony
Given two problems:
Problem A: Tau = Integral(0 to v)
v/(q^2 - v^2) dv
q = constant
Problem B: Tau = Integral(V TO 0)
v/(q^2 - v^2) dv
q = constant
Why is it that, SUBSTITUTION RULE is used in problem A, and QUOTIENT RULE is used in problem B? The two problems are somewhat similar. The only different is their integrals. Problem A, the integration is from 0 to V and problem B, the integration is from V to 0. The answers are shown below. Please help!!
Answer (problem A):
Tau = ln(q^2/(q^2-v^2))
Answer (problem B):
Tau = ln((q^2-v^2)/q^2)
Problem A: Tau = Integral(0 to v)
v/(q^2 - v^2) dv
q = constant
Problem B: Tau = Integral(V TO 0)
v/(q^2 - v^2) dv
q = constant
Why is it that, SUBSTITUTION RULE is used in problem A, and QUOTIENT RULE is used in problem B? The two problems are somewhat similar. The only different is their integrals. Problem A, the integration is from 0 to V and problem B, the integration is from V to 0. The answers are shown below. Please help!!
Answer (problem A):
Tau = ln(q^2/(q^2-v^2))
Answer (problem B):
Tau = ln((q^2-v^2)/q^2)
Answers
Answered by
drwls
One integral is the negative of the other, since the integrand is the same and only the direction of integration changes. If you think about the answers, and recognize that log a/b = - log b/a, you will see that all that is involved is a sign change there also. Either integration could have been solved by either method.
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