Let H be the distance of the sill (base)of the upper window from the roof. The tile passes it in time
T = sqrt (2H/g)
You also know that
T + 0.35 = sqrt [2(H + 2.45)/g]
Solve those two simulataneous equations for H. T is easily eliminated.
0.35 = sqrt[2(H + 2.45)/g] - sqrt(2H/g)
Now solve for H
A roofing tile falls from rest off the roof of a building. An observer from across the street notices that it takes 0.35 s for the tile to pass between two windowsills that are 2.45 m apart. How far is the sill of the upper window from the roof of the building?
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