Two numbers whose sum is 30 and product is 8800.
This problem cannot be solved in the real domain. It has a solution, however, in complex numbers.
Let x and y be the numbers.
(x+y)=30 => y=30-x
xy=8800 => x(30-x)=8800 =>
x²-30x+8800=0
Solve by the quadratic formula:
x=(30±√((-30)²-35200))/2
=15±5√7³ i
Two numbers whose sum is 30 and product is 8800? How do I find that?
1 answer