Vo = 235m/s @ A-deg.
Yo = ver. = 34.3m/s.
sinA = Yo / r = 34.3 / 235 = 0.14595,
A = 8.393.
Xo = hor. = r*cosA = 235*cos8.393 = 232.5m/s.
_____________m/s
Yo = ver. = 34.3m/s.
sinA = Yo / r = 34.3 / 235 = 0.14595,
A = 8.393.
Xo = hor. = r*cosA = 235*cos8.393 = 232.5m/s.
In this case, the vertical component of the velocity represents the length of one side of the right triangle, and the horizontal component of the velocity represents the length of the other side. The speed of the plane, which is the magnitude of the total velocity, represents the hypotenuse.
So, using the Pythagorean theorem, we have:
(speed of the plane)^2 = (vertical component of the velocity)^2 + (horizontal component of the velocity)^2
Plugging in the given values:
(235 m/s)^2 = (34.3 m/s)^2 + (horizontal component of the velocity)^2
Simplifying:
55125 m^2/s^2 = 1174.49 m^2/s^2 + (horizontal component of the velocity)^2
Subtracting 1174.49 m^2/s^2 from both sides:
(horizontal component of the velocity)^2 = 53950.51 m^2/s^2
Taking the square root of both sides:
horizontal component of the velocity = √53950.51 m/s
Calculating the square root:
horizontal component of the velocity ≈ 232.33 m/s
Therefore, the magnitude of the horizontal component of the plane's velocity is approximately 232.33 m/s.