A ball on the end of a string is whirled around in a horizontal circle of radius 0.22 m. The plane of the circle is 1.69 m above the ground. The string breaks and the ball lands 2.68 m away from the point on the ground directly beneath the ball’s location when the string breaks.

Question

A ball on the end of a string is whirled around in a horizontal circle of radius 0.22 m. The plane of the circle is 1.69 m above the ground. The string breaks and the ball lands 2.68 m away from the point on the ground directly beneath the ball’s location when the string breaks.
The acceleration of gravity is 9.8 m/s2 .
Find the centripetal acceleration of the ball during its circular motion.

so do i start by calculating the centripetal acceleration?

squires · Accepted Answer

i figured it out if anyone would like me to work out the process let me know =]