Asked by Anonymous

If a stone is thrown upward at 29.7 m/s, what will be its velocity at a height of 12 meters?
Answered by Henry
Vf^2 = Vo^2 + 2gd,
Vf^2 = (29.7)^2 + 2(-9.8)*12 = 646.89,
Vf = 25.4m/s.