Asked by Anonymous
If a stone is thrown upward at 29.7 m/s, what will be its velocity at a height of 12 meters?
Answers
Answered by
Henry
Vf^2 = Vo^2 + 2gd,
Vf^2 = (29.7)^2 + 2(-9.8)*12 = 646.89,
Vf = 25.4m/s.
Vf^2 = (29.7)^2 + 2(-9.8)*12 = 646.89,
Vf = 25.4m/s.
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