Asked by Anonymous
                If a stone is thrown upward at 29.7 m/s, what will be its velocity at a height of 12 meters?
            
            
        Answers
                    Answered by
            Henry
            
    Vf^2 = Vo^2 + 2gd,
Vf^2 = (29.7)^2 + 2(-9.8)*12 = 646.89,
Vf = 25.4m/s.
    
Vf^2 = (29.7)^2 + 2(-9.8)*12 = 646.89,
Vf = 25.4m/s.
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