Asked by lindsey
A bike first accelerates from 0.0 m/s to 5.0 m/s in 4.5 s, then continues at this constant speed for another 4.5 s. What is the total distance traveled by the bike?
Answers
Answered by
Damon
phase 1
a = (5-0)/4.5 = 1.11 m/s^2
v = 0 + a t = 1.11*4.5 = 5 sure enough
d = 0 + 0 (4.5) + (1/2)(1.11)(4.5)^2 =11.2
then phase 2
a = 0
v = 5
d = 11.2 + 5 (4.5) + 0
= 11.2 + 22.5 = 33.7 meters
a = (5-0)/4.5 = 1.11 m/s^2
v = 0 + a t = 1.11*4.5 = 5 sure enough
d = 0 + 0 (4.5) + (1/2)(1.11)(4.5)^2 =11.2
then phase 2
a = 0
v = 5
d = 11.2 + 5 (4.5) + 0
= 11.2 + 22.5 = 33.7 meters
Answered by
Anonymous
33.7
Answered by
Angel
It's actually 33.8
Answered by
fariha
thank you
Answered by
biiiiiiiiiiooo
33.87
Answered by
cyka blyat
thank you I am Russian you blyat
Answered by
john kenndy
i’m alive
Answered by
trump
did i ask?
Answered by
emanuel k.
brendan a bx