Asked by Amber
Find the intercepts of the graph of x^2 + y^2 + 4xy - 2x + 7y = 8
Answers
Answered by
Reiny
for x-intercept , let y = 0
x^2 + 0 + 0 - 2x + 0 = 8
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2
so the x-intercepts are (4,0), and (-2,0)
for the y-intercepts, let x = 0
0+y^2 + 0 - 0 + 7y =8
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you finish it, let me know what you get.
x^2 + 0 + 0 - 2x + 0 = 8
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2
so the x-intercepts are (4,0), and (-2,0)
for the y-intercepts, let x = 0
0+y^2 + 0 - 0 + 7y =8
..
..
you finish it, let me know what you get.