Asked by Ramesh Reddy
I will be thankfull to you if you help me to solve the below problem: 6√x-11/3√x=2√x+1/√x+6
I tried to solve the above problem like this:
(6√x-11)(√x+6)=(3√x)(2√x+1)
6√x(√x+6)-11(√x+6)=(3√x)(2√x)+(3√x)(1)
6x+36√x-11√x-66=6x+3√x
36√x-11√x-66=3√x
36√x=3√x+11√x+66
36√x=14√x+66
36√x-14√x=66
22√x=66
2√x=6
√x=6/2
√x=3
x=(3)2
x=9.
I tried to solve the above problem like this:
(6√x-11)(√x+6)=(3√x)(2√x+1)
6√x(√x+6)-11(√x+6)=(3√x)(2√x)+(3√x)(1)
6x+36√x-11√x-66=6x+3√x
36√x-11√x-66=3√x
36√x=3√x+11√x+66
36√x=14√x+66
36√x-14√x=66
22√x=66
2√x=6
√x=6/2
√x=3
x=(3)2
x=9.
Answers
Answered by
bobpursley
check your answer: sqrt 9 is 3
6*3-11)(3+6)=(9)(7)
7*9=9*7
correct
6*3-11)(3+6)=(9)(7)
7*9=9*7
correct
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