Asked by Henry
so this problem tells me to find the thickness of one atomic layer of gold using the volume occupied by one gold atom (1.73*10^-23) which i found from the previous problem
idk but is thickness the same as volume?
from the previous question it also gives me the density of gold metal- 18.9 g/cm^3
idk but is thickness the same as volume?
from the previous question it also gives me the density of gold metal- 18.9 g/cm^3
Answers
Answered by
bobpursley
If it is spherical,assume the thickness is diameter
volume=4/3 PI (D/2)^3
(d/2)^3= 3*volume/(PI*4)
d/2=cubrt( )
d=2 cubrt(3Volume/(PI*4))
volume=4/3 PI (D/2)^3
(d/2)^3= 3*volume/(PI*4)
d/2=cubrt( )
d=2 cubrt(3Volume/(PI*4))
Answered by
andrea
this is the right anwer
so
d= 3.21 x 10^(-10) m
so
d= 3.21 x 10^(-10) m
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