Asked by rafay
The melting of 0.140 g of Br2 (which occurs at -7.2 C at 1 atm pressure) absorbs 9.43 J of heat. Compute the enthalpy change in 2.00 mol of Br2 when it freezes.
Answers
Answered by
DrBob222
Convert 2.00 mol Br2 to grams.
moles = grams/molar mass.
9.43 J x (? g Br2/0.140 g Br2) = xx J.
moles = grams/molar mass.
9.43 J x (? g Br2/0.140 g Br2) = xx J.
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